20x/4x^2=5^3

Solution for 20x/4x^2=5^3 equation:

20x/4x^2=5^3

We move all terms to the left:

20x/4x^2-(5^3)=0


Domain of the equation: 4x^2!=0

x^2!=0/4

x^2!=√0

x!=0

x∈R


We add all the numbers together, and all the variables

20x/4x^2-125=0

We multiply all the terms by the denominator


20x-125*4x^2=0

Wy multiply elements

-500x^2+20x=0

a = -500; b = 20; c = 0;
Δ = b2-4ac
Δ = 202-4·(-500)·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(20)-20}{2*-500}=\frac{-40}{-1000}
=1/25
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(20)+20}{2*-500}=\frac{0}{-1000}
=0
$